As drawn, in the static case (i.e. assuming fluid flow rates low enough to maintain equilibrium conditions): 3 & 4 will be full (first) at exactly the same time. If fluid viscosity is significant, all bets are off but conditions would tend to favor #3. If fluid viscosity is very high, it will overflow beaker #1 first.
(And yes, the airplane will fly.)
[This message has been edited by Marvin McInnis (edited 10-27-2016).]
As drawn, and assuming equilibrium fluid flow: 3 & 4 will be full (first) at exactly the same time. If fluid viscosity is significant, all bets are off but conditions would tend to favor #3.
(And yes, the airplane will fly.)
I'll drink what ever one fills first, as long as it's beer.
Lacking additional data, we are forced to *assume* that the flow rate out of the faucet into container #1 is *equal* to, or less than, the flow rate of the tube connecting #1 and #2.
IF the flow rate out of the faucet is sufficiently higher than the flow capacity of the tube connecting #1 and #2, then even allowing for P= 0.43 X h, ( static pressure increase ), container #1 *could* fill first.
[This message has been edited by randye (edited 10-25-2016).]
If the flow out of the faucet is less than the flow capacity of the tubes, 3 and 4 fill at the same time. If the flow rate out of the faucet is faster than the capacity of the tubes, then 1 will always fill first.
assuming 3 & 4 are at the exact same level - it appears so in the picture assuming the tubes all flow the same rate
OK. Which one will be the last to be full? (assuming no flow restrictions in any of the interconnecting tubes)
I would say #4 would be the last one full. It would be just a fraction later than #3. #1 and #2 won't ever fill, the fluid will spill out of the top of #3 and #4 before 1 and 2 can fill.
If you look very closely at the image, beaker #4 is ever-so-slightly taller than #3. That means #4 can never be completely full, because #3 will overflow first. So only beaker #3 can fill completely. Beaker #4 will be almost full. Beaker #2 will never fill higher than the top of beaker #3. And beaker #1 will never fill higher than its output tube.
Of course, this assumes the flow rate of the spigot is lesser than or equal to the flow rates of the interconnecting tubes.
3 will fill to the bottom of the fill tube of 4 then 4 will start to fill. Once 3 & 4 are filled they will begin to over flow, 1 & 2 will never fill because 3 & 4 are lower and will over flow before they would reach full levels of liquid.
Dependant on whether the flow rate into #3 overwhelms the tube to #4, both will fill at the same time. They are effectively the same tank due to the configuration of the interconnecting piping. I designed and used setups like this in waste water treatment systems and rinse tank systems in the electroplating industry for decades. If the flow rate into #3 is greater than the flow capacity of the connecting piping, then #3 will fill first.
If, filled means to the brim, Three must be filled the spout point to begin passing fluid onto 4 but, once the fluid in 4 has reach the fill point, three will reach it's brim slightly ahead of 4.
Yes, the plane will take off!! ------------------ Ron
Isn't it strange that after a bombing, everyone blames the bomber, his upbringing, his environment, his culture, his mental state but … after a shooting, the problem is the gun?
Definition of a home owner, "see the door threshold, without my permission, there and no futher.......
If, you wish to piss off a Conservative, lie to him. If, you wish to piss off a Socialist, Liberal or Progressive, tell them the truth.
[This message has been edited by blackrams (edited 10-26-2016).]
Originally posted by Blacktree: If you look very closely at the image, beaker #4 is ever-so-slightly taller than #3. That means #4 can never be completely full, because #3 will overflow first. So only beaker #3 can fill completely. Beaker #4 will be almost full. Beaker #2 will never fill higher than the top of beaker #3. And beaker #1 will never fill higher than its output tube.
Given how slim the margin is, did you take into account the surface tension of the fluid? #3 could be ever so slightly overfull before it breaks surface tension and runs down the side. That could be enough to make up for the tiny difference between #3 and #4 or are you assuming the fluid is a perfectly straight line?
The photo appears to be a drawing on a chalk board. What is the precision level offered by a drawing utensil the size of a stick of chalk? All arguments have to make assumptions in the absence of explicitly stated info. You're assuming #4 is taller by a fraction that appears to be smaller than the lines used to make the drawing.
I would offer some general assumptions: All beakers are the same size. #1 is higher than #3 & #4. #2 is higher than #3 & #4 but lower than #1. #4 & #3 are at the same height level. All tubes between beakers have the same flow capacity. The flow from the faucet into #1 is less than the flow capacity of the tubes between the beakers. Optional: Assume fluid is water since the drawing appears to be a typical hose bib.
Measure with micrometer. Mark with chalk. Cut with chainsaw.
(an answer cannot be more precise than the data use to reach the conclusion)
[This message has been edited by Formula88 (edited 10-27-2016).]
I'll add to my post. Not only will 4 fill first, it will be the only one to fill and overflow.
Kevin
Once full, both three and four will overflow. One and two will never fill, this assumes the flow rate through the escape spouts is low enough to not overcome their capability to dispense the liquid.
------------------ Ron
Isn't it strange that after a bombing, everyone blames the bomber, his upbringing, his environment, his culture, his mental state but … after a shooting, the problem is the gun?
Definition of a home owner, "see the door threshold, without my permission, there and no futher.......
If, you wish to piss off a Conservative, lie to him. If, you wish to piss off a Socialist, Liberal or Progressive, tell them the truth.
Once full, both three and four will overflow. One and two will never fill, this assumes the flow rate through the escape spouts is low enough to not overcome their capability to dispense the liquid.
No, and yes.
First part would be yes if the connecting tube went straight across. That tube is the part throwing everyone.
[This message has been edited by Lambo nut (edited 10-27-2016).]
I don't know. I'm still trying to figure out how come my glass won't stay full.
Willie, There's a hole in the top of it!!!
------------------ Ron
Isn't it strange that after a bombing, everyone blames the bomber, his upbringing, his environment, his culture, his mental state but … after a shooting, the problem is the gun?
Definition of a home owner, "see the door threshold, without my permission, there and no futher.......
If, you wish to piss off a Conservative, lie to him. If, you wish to piss off a Socialist, Liberal or Progressive, tell them the truth.
As drawn, in the static case (i.e. assuming fluid flow rates low enough to maintain equilibrium conditions): 3 & 4 will be full (first) at exactly the same time. If fluid viscosity is significant, all bets are off but conditions would tend to favor #3. If fluid viscosity is very high, it will overflow beaker #1 first.
(And yes, the airplane will fly.)
Same thoughts I had looking at it except I also thought if fluid supply rate is higher than the out port can flow, 1 will fill first and eventually overflow.
I still say 3.. but they left out information that I am basing my answer off of.. the left off measurement graduations and where they stop at the top end of the beaker.. but if you go by where the last measurement graduation is on most, #3 fills first.. if you look at as the beaker almost overflowing, that is overfilled.. but they left that measurement graduation out of the formula and photo/chalkboard question
